Строки (C)

Строки

• Управление строками (CRT)
• Строковые литералы в C (справка Микрософт)
• Строки (tutorialspoint)

 1 #include <stdio.h>
 2 #include <stdbool.h>
 3 #include <string.h>
 4 
 5 int main() {
 6     char ch = '0';
 7     printf("Char %c has code %d\n", ch, ch);
 8     int code = 55;
 9     printf("Char %c has code %d\n", code, code);
10 
11     char* str = "Hello";
12     printf("String length %s = %d\n", str, strlen(str));
13 
14     bool hasl;
15     if (strchr(str, 'l') != NULL) {
16         hasl = true;
17     } else {
18         hasl = false;
19     }
20     printf("String %s has letter l = %s\n", str, hasl? "true" : "false");
21 
22     bool hasz;
23     if (strchr(str, 'z') != NULL) {
24         hasz = true;
25     } else {
26         hasz = false;
27     }
28     printf("String %s has letter z = %s\n", str, hasz? "true" : "false");
29 }

Задачник

• Строки

24

 1 #include <stdio.h>
 2 #include <string.h>
 3 
 4 int main() {
 5     char* binStr = "101001";
 6     // char binStr[20];
 7     // scanf("%s", &binStr);
 8 
 9     int multiplier = 1;
10     int dec = 0;
11 
12     for (int i = strlen(binStr)-1; i >= 0; i--) {
13         if (binStr[i] == '1') {
14             dec += multiplier;
15         }
16         multiplier *= 2;
17     }
18 
19     printf("%s\n%d", binStr, dec);
20 }